Biswa and Restaurant Business

Limits 3s, 512 MB

After huge success in Borhani business, Biswa has recently started restaurant business. He’s got the information about the numbers of customers for NN days, a sequence of NN integers a1,a2,,aNa_1, a_2, …, a_N. He wants to calculate the popularity of his restaurant from this data. First he’ll choose a window of size KK (KNK ≤ N). Then for each K-sized window from the original sequence (first KK-sized window will contain a1,a2,,aKa_1, a_2, …, a_K, second one will contain a2,a3,,aK+1a_2, a_3, …, a_{K+1}, and so on), he’ll calculate the number of all possible continuous increasing sequences in it and write them down in order. It’ll create a sequence of NK+1N - K + 1 integers b1,b2,,bNK+1b_1, b_2, …, b_{N-K+1}. Finally he’ll run the following function on the later found sequence:

Output of this function is the popularity that Biswa desires to calculate.

A sequence is increasing if for every two adjacent elements in it, the later one is greater than the previous one. A sequence containing a single element is considered to be a increasing sequence as well.

Input

First line of the test case contains a positive integer TT (0<T100 < T ≤ 10) denoting the number of scenarios. For each scenario the first line will contain two positive integers NN and KK (1KN1051 ≤ K ≤ N ≤ 10^5). The second line contains a sequence a1,a2,,aNa_1, a_2, …, a_N (1ai1051 ≤ a_i ≤ 10^5), where aia_i equals to the number of customers on ii-th day.

Output

For each scenario, output a single integer - the popularity in a separate line. The answer may be large so compute it modulo 109+710^9+7.

Sample

InputOutput
1
4 3
1 2 3 2
16

In the sample test the sequence is: 1, 2, 3, 2 and the window size is 3. The first window will contain 1, 2, 3 and 6 possible continuous increasing sequences can be found there: {1,2,3}\{1, 2, 3\}, {1,2}\{1, 2\}, {2,3}\{2, 3\}, {1}\{1\}, {2}\{2\}, {3}\{3\}. Similarly the second window will contain 4 continuous increasing sequences: {2,3}\{2, 3\}, {2}\{2\}, {3}\{3\}, {2}\{2\}. So the sequence bb is: 6, 4 and if we run that function on it we’ll get 16 which is also 16 in modulo 109+710^9+7.