Problem Name: Nodes and Depth
Problem setter: Mb. Abdul Alim
Limits 1s, 512 MB
To solve this problem, we can observe that the number of nodes at each depth follows a geometric progression with a common ratio of 3. Specifically, the number of nodes at depth D can be calculated as 3^D.
We can find the total number of nodes up to depth N by summing the number of nodes at each depth from 1 to N. This sum can be calculated using the formula for the sum of a geometric series:
Total nodes = a1 (r^N - 1) / (r-1) + 1; (Depth 0 = 1 Node)
where:
a1 is the first term in the series (number of nodes at depth 1),
r is the common ratio (3 in this case)
N is the depth.
Here's the approach in a paragraph:
We start by reading the input value of N. Then, we apply the formula for the sum of a geometric series to calculate the total number of nodes up to depth N, using a1 = 3 ( number of nodes at depth 1) and r = 3 (common ratio). Finally, we output the result, which represents the total number of nodes within depth N.
Complexity:
Time Complexity: O(N)
Space complexity: O(1)