**Category: Simple Math**

**Problem Analysis:**

**Observation:** This problem can be solved by simple iteration or by using mathematical observations. As the problem category is Simple Math, let’s solve it with math.

Let’s forget about the term

**“Buy 2 Get 1”**. How many pizzas actually you can buy?If for buying $2$ pizzas, you’re getting $1$ additional pizza for free, then for buying

**$C$**pizzas, how many additional pizzas will you get?

**Solution Idea:**

If the pizza price is

**$X$**, and the dollar you have is**$M$**. Then the total number of pizzas you can buy is, $C = M/X$For example, $M = 20$, $X = 6$, then $C = (20/6) = 3$.

Now you have the

**$C$**. So, the additional pizzas you will get will be,$=C/2$

$= (M/X)/2$ [ As, $C = M/X$]

$= M/(2*X)$

So, total number of pizzas will be $= (M/X) + {M/(2*X)}$

**Special Thanks:** Md. Albin Hossain

```
Source Code:
#include <stdio.h>
int main(){
int test_case;
scanf("%d", &test_case);
while(test_case--){
int m, x;
scanf("%d %d", &m, &x);
int pizza_count = (m / x) + (m / (2 * x));
printf("%d\n", pizza_count);
}
return 0;
}
```

92%
Solution Ratio

steinumEarliest,

user.3193Fastest, 0.0s

Monjurul.9781Lightest, 4.9 MB

ItzRAYShortest, 93B

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