The total probability of a sample space is 1. So if the probability of choosing a square is subtracted from 1 then we will find the probability of choosing a rectangle that is not a square. The cardinality of choosing a rectangle from N x N chessboard is n+1 choose 2 multiplied by n+1 choose 2. And the cardinality of choosing a square from the N x N chessboard is n(n+1)(2n+1) / 6. So the probability choosing a rectangle that is not a square will be $1 - ( (n ( n + 1)(2n + 1) / 6 ) / {n+1 \choose 2}^{2} )$

94%
Solution Ratio

tanvirtareqEarliest,

S_SubrataFastest, 0.0s

tanvirtareqLightest, 131 kB

anonyo.akandShortest, 123B

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