# Practice on Toph

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# Total Hamming Distance

By RasheedAbid · Limits 2s, 1.0 GB

The Hamming distance between two integers is the number of positions at which the corresponding bits are different.
Now your job is to find the total Hamming distance between all pairs of the given numbers. For example, if the input array is [4, 14, 2], the output will be 6.

Explanation: In binary representation, the 4 is 0100, 14 is 1110, and 2 is 0010 (just showing the four bits relevant in this case). So the answer will be:

HammingDistance(4, 14) + HammingDistance(4, 2) + HammingDistance(14, 2) = 2 + 2 + 2 = 6.

## Input

Input starts with an integer T, denoting the number of test cases (0 < T ≤ 10). Each test case consists of two lines. The first line contains a positive integer N, the size of the array (0 < N ≤ 105). The next line contains the N space separated integers a1, a2, … , aN (0 ≤ ai ≤ 1012).

## Output

For each test case, print the total hamming distance of the given numbers.

## Sample

InputOutput
1
3
4 14
6

### Statistics

73% Solution Ratio

BRUR_DivByZeroEarliest, Oct '17

rafi_1703076Fastest, 0.2s

BRUR_DivByZeroLightest, 131 kB

krishnaShortest, 420B

### Submit

 Replay of 18th IUT Computer Programming Contest 2017 Oct '17 18th IUT Computer Programming Contest 2017 Oct '17 